tolong jawab dengan caranya ya plisss cari luasnya

no 1= trapesium 6+14:2*10=100*2=200
persegipanjang 8*22=176
segitiga 10*8:2=40
total =200+176+40=416

no.1
luas p.panjang = 22×8 = 176 cm^2
luas 2 trapesium = 2(20×10/2) = 200cm^2
luas segitiga = 1/2× 8 ×10 = 40cm^2

jmlah slruh = 176 + 200 +40 = 416 cm^2
no.2
luas layang2 = (diagonal 1 + diagonal2)/2
=(10+12)/2
= 11 cm^2
luas bola = phi×r^2
= 3,14 × 5^2
= 78,5 cm^2
luas slruh = 11 + 78,5
= 89,5 cm^2
no.3
l = 1/2×p
=1/2×24= 12

luas p.panjang
p×l = 24 × 12 = 288 cm^2

Trapesium
t = 28 - 12 = 16
luas = (jmlah dua sisi sjjr)×t /2
=(24 + 12)× 16 / 2 = 36×16 /2
= 288 cm^2
jumlah seluruh = 288+288 = 576cm^2

no.4
luas segitiga = 1/2×6×8
= 24 cm^2
luas trapesium
(rumus sprti di no.3)

(6+15)×8/2
=21×4
=84 cm^2

luas seluruh = (24 + 84)cm^2
= 108 cm^2


good luck
jdikan jwbn terbaik ya...please....