Diketahui f(x)=√ x+1 +3 dan g(x)=4x2 -4x.rumus komposisi fungsi (f◦g)(x)=

langsung aja y

(fog)(x) = f{g(x)}

= √g(x)+1 + 3

= √ 4x²-4x+1 + 3

semoga berguna +_+

f(x) = √(x + 1) + 3
g(x) = 4x^2 - 4x
(f o g)(x) = f(g(x))
= √(g(x) + 1) + 3
= √(4x^2 - 4x + 1) + 3
= √(2x - 1)^2 + 3
= (2x - 1) + 3
= 2x + 2

= 2(x + 1)