persamaan grafik fungsi kuadrat yang melalui titik A(3,0),B(2,0)dan C(0,-10)adalah...

x1 = 3
x2 = 2
(x,y) = (0,-10)
y = a(x - x1)(x - x2)
-10 = a(0 - 3)(0 - 2)
-10 = 6a
a = -10/6 = -5/3
y = -5/3(x - 3)(x - 2)
y = -5/3(x² - 5x + 6)
y = -5/3x² + 25/3x - 10