Jika diketahui Ka CH3COOH = 1×10^-5 larutan Ca(CH3COO)2 0,05 M mempunyai pH sebesar Mohon bantuannya

[OH-] = √10^-14/10^-5 × 5.10^-2 × 2
= √ 10^-9 × 10^-1
= √ 10^-10
= 10^-5
pOH = 5

pH = 14 - pOH = 14-5 = 9

[OH]= √kw/ka x M x b
=√10^-14/10^-5 x 5.10^-2 x 2
=√10^-9 x 10.10^-2
=√10^-10
=10^-5
pOh= 5
pH= 14-pOh=14-5= 9