Matematika

Pertanyaan

mohon bantu y kk no 11
sama jalanny y kk
terimah ksh y kk
mohon bantu y kk no 11 sama jalanny y kk terimah ksh y kk

2 Jawaban

  • pakai rumus y-y1/y2-y1 = x-x1/x2-x1

    y-1/6-1 = x-2/3-2

    y-1/5 = x-2/1

    5(x-2) = y-1
    5x-10 = y-1
    5x - y = -1 + 10
    5x - y = 9 (A)
  • (2,1) dan (3,6)
    x1= 2 x2= 3
    y1= 1 y2= 6

    y-y1/y2-y1 = x-x1/x2-x1
    y-1/6-1 = x-2/3-2
    y-1/5=x-2/1
    kali silang
    5(x - 2)= y - 1
    5x - 10 = y - 1
    5x - y - 10 = -1
    5x - y = -1 + 10
    5x - y = 9