Limit fungsi trigonometri (pakai cara) Thanks

lim x->0 (x^2+tan3x)/(3x+sin2x)
gunakan dalil L'hospital
lim x->0 (2x+3 tan3x sec 3x)/(3+2cos2x)
substitusi nilai x=0
=[2(0)+3tan3(0) sec 3(0)]/[3+2cos2(0)]
=(0+0)/(3+2)
=0/5
=0