Harga larutan ph NH3 0,001 M (kb = 10^-5) adalah

[OH-]=√kb.M
[OH-]=√10⁻⁵.10⁻³
[OH-]=√10⁻⁸
[OH-]=10⁻⁴

pOH = 4
pH = 14-4
pH=10

Untuk basa lemah,
[Oh-] = akar kb x MNh3
= akar 10^-5 x 10^-3
= 10^-4
Poh = -log [oh-]
Poh = -log 10^-4
Poh = 4

Ph = pkw - poh
Ph = 14-4
Ph = 10

Semoga membantu yah