cara nomor 2 gimana yaa ?

^4 log 3=a
^3 log 7=b
maka ^4 log 3.^3 log 7=^4 log 7=ab
^7 log 6=?

sifat log
^a log b=(^p log b)/(^p log a)
^a log bc=^a log b + ^a log c

^7 log 6 = (^4 log 6)/(^4 log 7)
=(^4 log 3 + ^4 log 2)/(^4 log 7)
=(a+½)/(ab)
=(2a+1)/(2ab)