Carilah penyelesaian dari sistem tiga variabel: x-y+z= 6 2x+y-2z= -1 3x+2y-2z= -2 Beri jalannya yaa

2x + 2y + z = 12
4x + 2y - 4z = -2
3x + 2y - 2z = -2

-5x + 7z = 16

eliminasi pers(1)dan(2)
x-y+z=6. |*2|2x-2y+2z=12
2x+y-2z=-1. |*1|2x+y-2z=-1. _
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-3y+4z=13....(4)
eliminasi pers(2)dan(3)
2x+y-2z=-1. |*3|6x+3y-6z=-3
3x+2y-2z=-2. |*2|6x+4y-4z=-4. -
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-y-2z=1.....(5)
eliminasi pers(4)dan(5)
-3y+4z=13. |*1|-3y+4z=13
-y-2z=1. |*3|-3y-6z=3. -
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10z=10
z=1
-y-2z=1
-y-2(1)=1
-y-2=1
y=-3
x-y+z=6
x-(-3)+1=6
x=2