jawaban.nya pakai cara ya,,buat besok

pytagoras = [tex] \sqrt 5^{2} -4^{2} [/tex] = [tex] \sqrt{25-16} [/tex] = [tex] \sqrt{9} [/tex] = 3 cm
alas atas trapesium = 11+2x3 = 17 cm
trapesium = [tex] \frac{1}{2} [/tex] . (a+b).t = 1/2(17+11).4 = 56 cm²
segitiga = 1/2 a.t = 1/2. 15.8 = 60 cm²
luas = trap+seg = 60 +56 = 116cm²

C.116 cm²