Diket ka= 1×10-5 berapa ml naoh 0,1 m dan larutan ch3cooh 0,1 m masing** diperlukan untum membuat 120 ml larutan penyangga dg ph 5
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Pertanyaan
Diket ka= 1×10-5 berapa ml naoh 0,1 m dan larutan ch3cooh 0,1 m masing** diperlukan untum membuat 120 ml larutan penyangga dg ph 5
1 Jawaban
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1. Jawaban entahlahhm
Mol CH3COOH = M x V = 0,1 x 120 = 12mmol
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PH = 5
[H+] = 10^-5
[H+] = ka x a/g
10^-5 = 10^-5 x a/12
10^-5/10^-5 = a/12
1 = a/12
a= 1 x 12 = 12mol
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a = M x V
12 = 0,1 x V
V = 12 / 0,1
= 120ml