nilai minimum fungsi f(x)=2(x-4)²+6

f(x) = 2 (x - 4)² + 6

f(x) = 2 (x² - 8x + 16) + 16

f(x) = 2x² -16x + 32 + 16

f(x) = 2x² -16x + 48

a = 2; b = -16; c = 48

................

Sumbu simetri

= -b/2a

= - (-16) / (2 . 2)

= 4

...............

f(x) = 2 . (x - 4)² + 6

f(4) = 2 . (4 - 4)² + 6

f(4) = 2 . 0 + 6

f(4) = 6

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Kelas 10

Pelajaran Matematika

Bab 2 Persamaan dan Fungsi Kuadrat

Kata kunci : -

Kode kategorisasi : 10.2.2