Matematika

Pertanyaan

suatu fungsi f di nyatakan dengan rumus f(x) = ax + b, jika f(3) =17 dan f (-2) = -3 maka nilai f(5) adalah

2 Jawaban

  • f(x) =ax + b
    f(-2) = -3 =(-2a) +b = -3
    f(3) = 17 = 3a +b = 17
    ------------------------------- -
    -5 a = - 20
    a = - 20 ÷ -5 = 4
    3a + b = 17
    3×4 +b =17
    12 +b =17
    b = 17-12 = 5
    f(×) =ax + b
    f(5) = (4 ×5) + 5
    = 20 +5 =25
    maaf kalau salah
  • f(x) = ax + b
    f(3) = 3a + b = 17
    f(-2) = -2a + b = -3
    _________________ -
                 5a = 20
                   a = 4

    -2a + b = -3
    -8 + b = -3
    b = 5

    f(x) = ax + b
    f(5) = 4(5) + 5
          = 25

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