jika cot beta = 4/3 tentukan nilai trigonometri berikut? sec beta dan ctg beta tolong yaa

cotB = 4/3 → x = 4 dan y= 3
r = √(x² + y²) = √(4² + 3²) = 5
secB = 1/cosB = 1/(x/r) = r/x = 5/4
cotB ← dah ada tuh dri soal....

cot = cotangen
ctg = cotangen