hitunglah kelarutan senyawa pbBr2 ksp=4,0×10^-5
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Pertanyaan
hitunglah kelarutan senyawa pbBr2 ksp=4,0×10^-5
1 Jawaban
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1. Jawaban icchan
PbBr2 => Pb²⁺ + 2Br-
s s 2s
Ksp PbBr2 = [Pb²⁺] [Br-]²
4 x10⁻⁵ = [s][2s]²
4s³ = 4 x10⁻⁵
s³ = 10⁻⁵
s = 2,15 x10⁻² mol/liter