6+3+3/2+... Jumlah 5 suku pertama deret tersebut adalah A.10 5/8 B.11 3/8 C.11 5/8 D.12 3/8

a = 6

b= 1/2

S5 = a(1-r^5)/1-r

= 6(1-(1/2)^5) /(1-1/2)

= 6 (31/32) × 2

= 12 (31/32)

= 6(31/16)

= 3(31/8)

= 93/8

= 11 5/8 (C)