Matematika

Pertanyaan

1. Lim x→0 1-cos2x per sin x =
2. Lim x→2 3x² - x - 10 per 4-2x =
3. Lim x→π/tan (x+π/3) per tan (x+π/3) = ...

1 Jawaban

  • limit

    1. lim(x->0 )  (1 -cos 2x) / sin x
    lim(x->0) (1 - (1 - 2 sin² x) / sin x
    lim(x->0)  (2 sin² x)/sin x
    lim (x->0) 2 sin x
    x = 0 -->limit = 2 sin (0) = 2(0) = 0

    2. lim (x->2)  3x² -x -10 / (4 -2x)
    lim(x->2) (x-2)(3x +5)/ (x-2)(-2)
    lim(x->2) (3x+5) /(-2)
    x = 2 --> limit = (3.2 -5)/(-2) = 1/(-2) = - 1/2.

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