Matematika

Pertanyaan

jika 4x + 5y = 30 dan yx + 8y = 40 tentukan nilai 3x-29

1 Jawaban

  • Eliminasi :
    4x + 5y = 30 |×8|
    yx + 8y = 40 |×5|
    _____________
    32x + 40y = 240
    5yx + 40y = 200
    ____________ _
    32x - 5yx = 40
    yx - 32x = 40/5
    yx - 32x = 8
    yx - x = 8/32
    y = 8/32
    y = 1/4

    Substitusi :
    yx + 8y = 40
    (1/4)x + 8(1/4) = 40
    1/4x + 2 = 40
    1/4x = 40 - 2
    1/4x = 38
    x = 38 x 4
    x = 152

    Dit :
    3x - 29
    3(152) - 29
    456 - 29 = 427

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