tolong jawab pake caranya....

l = 6 cm

mencari tinggi
L BCGF = l × t
54 = 6 × t
54/6 = t
9 = t
t = 9 cm

mencari panjang
L EFGH = p × l
72 = p × 6
72/6 = p
12 = p
p = 12 cm

L ABFE = p × t
= 12 × 9
= 108 cm2

luas seluruh sisi balok
= ( L BCGF × 2 ) + ( L EFGH × 2) + ( L ABFE × 2)
= (54 × 2) + (72 × 2) + (108 × 2)
= 108 + 144 + 216
= 468 cm2

maaf kalau salah