lim x->0 x3-3x2+6x/x2+2x

dianggap gini
lim x→0 (x³ - 3x² + 6x)/(x² + 2x)
= lim x→0 x(x² - 3x + 6)/(x(x + 2))
= lim x→0 (x² - 3x + 6)/(x + 2)
= (0 - 0 + 6)/(0 + 2)
= 3

lim x3-3x2+6x/x2+2x
x->0
lim (0)3-3(0)2+6(0)/2(0)+2(0)
      0-0+0/0+0
      =0

itu 2x atau x2?